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(4/(x-4))-(3/(x+1))=5/(x^2-3x-4)
We move all terms to the left:
(4/(x-4))-(3/(x+1))-(5/(x^2-3x-4))=0
Domain of the equation: (x-4))!=0
x∈R
Domain of the equation: (x+1))!=0
x∈R
Domain of the equation: (x^2-3x-4))!=0We calculate fractions
x∈R
((-3x+4*(x+1))*x^2)/((x-4))*(x+1))*(x^2-3x-4)))+(-(-3x+3*(x-4))*x^2)/((x-4))*(x+1))*(x^2-3x-4)))+(-(5*(x-4))*x)/((x-4))*(x+1))*(x^2-3x-4)))=0
We can not solve this equation
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